Question

13 units find area of sector GHJ. In circle H with m/GHJ 36 and GH Round to the nearest hundredth. H G

Answer 1

$\text{Area}_{cir\sec }=53.09\text{ square units}$

Explanation

The area of a circular sector is given by:

$\text{Area}_{cir\sec }=\pi r^2\cdot(\frac{\Theta}{360})$

where r is the radius and theta is the angle

then

Let

angle=36

radius=13

now ,replace.

$\begin{gathered} \text{Area}_{cir\sec }=\pi r^2\cdot(\frac{\Theta}{360}) \\ \text{Area}_{cir\sec }=\pi(13)^2\cdot(\frac{36}{360}) \\ \text{Area}_{cir\sec }=\pi\cdot169\cdot(\frac{36}{360}) \\ \text{Area}_{cir\sec }=53.0929 \\ \text{rounded} \\ \text{Area}_{cir\sec }=53.09\text{ square units} \end{gathered}$

I hope this helps you