Help in the Accompanying diagram of the circle O chord CD ….

Answer:
The length of ED is;
[tex]ED=8[/tex]Explanation:
Given the figure in the attached image.
Chord CD bisects chord AB at E.
So;
[tex]AE=EB=\frac{AB}{2}[/tex]Also applying the Bisecting chord formula;
[tex]AE\cdot EB=CE\cdot ED[/tex]Given;
[tex]\begin{gathered} CE=2 \\ AB=8 \\ AE=EB=\frac{AB}{2}=\frac{8}{2}=4 \\ AE=4 \\ EB=4 \end{gathered}[/tex]substituting the given values;
[tex]\begin{gathered} AE\cdot EB=CE\cdot ED \\ 4\cdot4=2\cdot ED \\ 16=2\cdot ED \\ ED=\frac{16}{2} \\ ED=8 \end{gathered}[/tex]Therefore, the length of ED is;
[tex]ED=8[/tex]