Solution
For this case we have the following situation:
[tex]h(t)=-16t^2+100t+5[/tex]And we want to find the time where h(t)=0 so we can do this:
[tex]-16t^2+100t-5=0[/tex]Solving for t we got:
[tex]t=\frac{-100\pm\sqrt[]{(100)^2-4(-16)(-5)}}{2\cdot(-16)}[/tex]Then the two possible solutions are:
t= 6.299 s or t= -0.049 s
Then the answer is:
O b. 6.3 seconds,