Respuesta :

Answer:

x = -13 or 1.

Explanation:

Given the equation:

[tex]12x=13-x^2[/tex]

Follow the steps below to solve by completing the square method:

Step 1: Take the constant to the right-hand side.

[tex]x^2+12x=13[/tex]

Step 2: Divide the coefficient of x by 2, square it and add it to both sides.

[tex]x^2+12x+6^2=13+6^2[/tex]

Step 3: Write the left-hand side as a perfect square.

[tex]\begin{gathered} (x+6)^2=13+36 \\ (x+6)^2=49 \end{gathered}[/tex]

Step 4: Take the square root of both sides.

[tex]\begin{gathered} x+6=\pm\sqrt[]{49} \\ x+6=\pm7 \end{gathered}[/tex]

Step 5: Solve for x.

[tex]\begin{gathered} x=-6\pm7 \\ \implies x=-6-7\text{ or }x=-6+7 \\ x=-13\text{ or }x=1 \end{gathered}[/tex]

The value of x is -13 or 1.

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