Answer:
x = -13 or 1.
Explanation:
Given the equation:
[tex]12x=13-x^2[/tex]Follow the steps below to solve by completing the square method:
Step 1: Take the constant to the right-hand side.
[tex]x^2+12x=13[/tex]Step 2: Divide the coefficient of x by 2, square it and add it to both sides.
[tex]x^2+12x+6^2=13+6^2[/tex]Step 3: Write the left-hand side as a perfect square.
[tex]\begin{gathered} (x+6)^2=13+36 \\ (x+6)^2=49 \end{gathered}[/tex]Step 4: Take the square root of both sides.
[tex]\begin{gathered} x+6=\pm\sqrt[]{49} \\ x+6=\pm7 \end{gathered}[/tex]Step 5: Solve for x.
[tex]\begin{gathered} x=-6\pm7 \\ \implies x=-6-7\text{ or }x=-6+7 \\ x=-13\text{ or }x=1 \end{gathered}[/tex]The value of x is -13 or 1.