Question

In this diagram, circle A has radius = 4.9 and DC = 8.1. BC is tangent line, calculate the distance of BC.

Answer 1

We have a tangent line that means the m

we have

AB= radius=4.9

AC=AD+DC=4.9+8.1=13

Because we have that m

$c^2=a^2+b^2$

where

a=AB=4.9

b=?=x

c=AC=13

we substitute the values

$\begin{gathered} b=\sqrt[]{13^2-4.9^2} \\ b=\sqrt[]{169-24.01} \\ b=\sqrt[]{144.99} \\ b=12.04 \end{gathered}$