Solution
Part A
The distance x
[tex]\begin{gathered} x^2=50^2+100^2 \\ \\ x=\sqrt{12500} \\ x=50\sqrt{5} \\ x=111.8033 \end{gathered}[/tex]Distance 112 (Nearest mile)
Part B
[tex]\begin{gathered} tan\theta=\frac{100}{50} \\ \theta=tan^{-1}2 \\ \theta=63.43^0 \end{gathered}[/tex]Direction 63 degree (Nearest degree)