This problem can be seen as the next equation
[tex]\begin{gathered} 4F+2H+1O=T \\ F\text{ = dollars spent on flights} \\ H\text{ = dollars spent at hotels} \\ O\text{ = dollars spent in other stuff} \\ T\text{ = total of points} \end{gathered}[/tex]Since he have charged 9480 dollars in total then we also have the next equation.
[tex]F+H+O=9480[/tex]With the rest of the information, we conclude the next system of equations
[tex]\begin{gathered} 4F+2H+O=14660 \\ F+H+O=9480 \\ F-2H=140 \end{gathered}[/tex]From the first two equations, we can substract them to obtain
[tex]\begin{gathered} 4F+2H+O=14660 \\ - \\ F+H+O=9480 \\ = \\ 3F+H=5180 \end{gathered}[/tex]If we multiply this last equation by 2 and add it to the last equation in the system we have
[tex]\begin{gathered} 6F+2H=10360 \\ + \\ F-2H=140 \\ = \\ 7F\text{ = }10500 \\ \end{gathered}[/tex]So
[tex]\begin{gathered} F=\frac{10500}{7}=1500 \\ H=\frac{1500-140}{2}=680 \\ O=9480-1500-680=7300 \end{gathered}[/tex]Then, he spent 1500 dlls. on flights, 680 dlls. at hotels and 7300 dlls. on others
[tex]\begin{gathered} 4\text{ 2 1 14660 } \\ 1\text{ 1 1 9480} \\ 1\text{ -2 0 140 }\approx \\ 4\text{ 2 1 14660 } \\ 3\text{ 1 0 5180} \\ 1\text{ -2 0 140 }\approx \\ 4\text{ 2 1 14660 } \\ 3\text{ 1 0 5180} \\ 7\text{ 0 0 }10500 \\ \end{gathered}[/tex]