Question

create 2 linear equations, in the form y=mx+b-the two lines are perpendicular to each other and both lines pass through the point (3,-5)

Answer 1

$\begin{gathered} y=x-8 \\ y=-x-2 \end{gathered}$

Explanation

Step 1

two lines are perpendicular if the producto of their slopes equals -1

so

$\begin{gathered} so\mathrm{}\text{let} \\ \text{slope}1|\cdot\text{solpe}2=-1 \\ \text{slope}1=1 \\ \text{slope}2=-1 \end{gathered}$

Step 2

now, find the equations

a) for line 1

Let

slope=1

point (3,-5)

to find the equation ,let's use the formula

$\begin{gathered} y-y_1=m(x-x_1) \\ \text{replace} \\ y-(-5)=1(x-3) \\ y+5=x-3 \\ \text{subtract 5 in both sides} \\ y+5-5=x-3-5 \\ y=x-8 \end{gathered}$

therefore, the equation 1 is

$y=x-8$

b) for line 2

let

slope=slope2=-1

point=(3,-5)

replace in the formula

$\begin{gathered} y-y_1=m(x-x_1) \\ y-(-5)=-1(x-3) \\ y+5=-x+3 \\ \text{subtract 5 in both sides} \\ y+5-5=-x+3-5 \\ y=-x-2 \end{gathered}$

, therefore, the equations are

$\begin{gathered} y=x-8 \\ y=-x-2 \end{gathered}$

I hope this helps you