Question

y(s)= int 0 ^ e^ 4 cos z^ 0 z^ 2 dx then; y^ prime (s)=

Answer 1

Given the following integral:

$y(s)=\int\frac{cos\text{ }z^9}{z^2}dz$

We will find y'(s)

As we know the integral is the inverse of the differentiation

So, the first derivative of the integral can be obtained by removing the integral sign

So, the answer will be:

$y^{\prime}(s)=\frac{cos\text{ }z^9}{z^2}$