We will have the following:
First, we determine the wavelength, that is:
[tex]\begin{gathered} \lambda=\frac{346m/s}{384Hz}\Rightarrow\lambda=\frac{173}{192}m \\ \\ \Rightarrow\lambda\approx0.9m \end{gathered}[/tex]Now, we determine the 1st, 2nd and 3rd harmonics, that is:
*1st harmonic:
[tex]\begin{gathered} L=\frac{1}{2}\lambda\Rightarrow L\approx\frac{1}{2}(0.9m) \\ \Rightarrow L\approx0.45m \end{gathered}[/tex]So, the first harmonic will be found approximately at 0.45 m.
*2nd harmonic:
[tex]L=\frac{2}{2}\lambda\Rightarrow L\approx0.9m[/tex]So, the second harmonic will be located at approximately 0.9 m.
*3rd harmonic:
[tex]\begin{gathered} L=\frac{3}{2}\lambda\Rightarrow L\approx\frac{3}{2}(0.9m) \\ \\ \Rightarrow L\approx1.35m \end{gathered}[/tex]So, the third harmonic is located at approximately 1.35 m.