Given:
[tex]\begin{gathered} l=11y+1 \\ w=y-7 \end{gathered}[/tex]Required:
To find the perimeter and area hallway.
Explanation:
Area :
[tex]\begin{gathered} A=lw \\ \\ =(11y+1)(y-7) \\ \\ =11y^2-77y+y-7 \\ \\ =11y^2-76y-7 \end{gathered}[/tex]Perimeter :
[tex]\begin{gathered} P=2(l+w) \\ =2(11y+1+y-7) \\ =2(12y-6) \\ =24y-12 \end{gathered}[/tex]Final Answer:
Area :
[tex]11y^2-76y-7[/tex]Perimeter :
[tex]24y-12[/tex]