For rectangle ABCD, if DC =16.4 ft and BC = 14.8 ft, find DB+AC

Recall that one property of a rectangle is that opposite sides are always equal.
Therefore, we can say that:
DC = AB
BC = AD
Because of this, we can also say that DB = AC.
Given:
DC = 16.4 ft.
BC = 14.8 ft.
Using the Pythagorean Theorem, let's find DB.
[tex]\begin{gathered} \text{ c}^2=a^2+b^2 \\ \text{ DB}^2=DC^2+BC^2 \\ \text{ DB}^{}=\sqrt{DC^2+BC^2} \end{gathered}[/tex][tex]\text{ DB = }\sqrt[]{16.4^2+14.8^2}\text{ = }\sqrt[]{268.96\text{ + 219.04}}[/tex][tex]\text{ DB = }\sqrt[]{488}\text{ }\approx\text{ 22.1 ft.}[/tex]Since DB = AC, DB + AC will be:
[tex]\text{ DB + AC = DB + DB = 2DB}[/tex][tex]\text{ 2(22.1) = 44.2 ft.}[/tex]Therefore, DB + AC = 44.2 ft.
The answer is Choice B.