Hello!
We have the following system:
[tex]\begin{cases}y\le|x| \\ y<-2x-1\end{cases}[/tex]
To solve this exercise, we can try all alternatives and check which of them are true. Let's do it:
A) (3, 1) false
[tex]\begin{cases}1\le|3|\text{ ok} \\ 1<-2\cdot3-1\rightarrow1<-6-1\rightarrow1<-7\text{ not ok}\end{cases}[/tex]
B) (2, -1) true
[tex]\begin{cases}-1\le|2|\text{ ok} \\ -1<(-2\cdot-1)-1\rightarrow-1<2-1\rightarrow-1<1\text{ ok}\end{cases}[/tex]
C) (0, 4) false
[tex]\begin{cases}4\le|0|\text{ not ok} \\ 4<-2\cdot0-1\rightarrow4<-1\text{ not ok}\end{cases}[/tex]
D) (-3, 1)