Given:
The initial speed of the train is,
[tex]u=60\text{ m/s}[/tex]The time to stop is,
[tex]\begin{gathered} t=1\text{ m 25 s} \\ =(60+25)\text{ s} \\ =85\text{ s} \end{gathered}[/tex]The final speed is,
[tex]v=0[/tex]To find:
The acceleration
Explanation:
Using the formula of speed,
[tex]v=u+at[/tex]Here, a is the acceleration.
Substituting the value we get,
[tex]\begin{gathered} 0=60+a\times85 \\ a=-\frac{60}{85} \\ a=-0.71\text{ m/s}^2 \end{gathered}[/tex]Hence, the acceleration is,
[tex]a=-0.71\text{ m/s}^2[/tex]