Question

Help me solve this, I already figured out how to do the first part I’m just confused on part b.

Answer 1

we have the function

$f(x)=\frac{3}{5x+11}$

Part A

Remember that

the denominator cannot be equal to zero

so

5x+11=0

5x=-11

x=-11/5

therefore

the value of x can not be equal to x=-11/5

the domain is the interval (-infinite, -11/5) U (-11/5, infinite)

Part B

Find f(1)

Remember that

f(1) is the value of f(x) when the value of x=1

substitute

$f(1)=\frac{3}{5(1)+11}$$f(1)=\frac{3}{16}$

and the coordinates of the point are (1,3/16)

x=1

y=3/16