Question

Find the equation of the circle of center (-3,8) and radius 12 units.

Answer 1

The equation of the circle with center (a,b) and radius R can be written as:

$(x-a)^2+(y-b)^2=R^2$

If the center is (a,b)=(-3,8) and R=12, we have:

$\begin{gathered} (x+3)^2+(y-8)^2=12^2 \\ (x+3)^2+(y-8)^2=144 \end{gathered}$

The equation of the circle is (x+3)^2+(y-8)^2=144.