Explanation
We can find the magnitude of the given vectors below.
Part A
[tex]||4,4||=\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}[/tex]Answer: 4sqrt(2)
Part B
[tex]||\left(-10,10\right)||=\sqrt{10^2+(-10)^2}=\sqrt{100+100}=\sqrt{200}=10\sqrt{2}[/tex]Answer: 10sqrt(2)
Part C
[tex]||7,-7||=\sqrt{7^2+(-7)^2}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}[/tex]Answer: 7sqrt(2)
Part D
[tex]||\left(-2,-10\right)||=\sqrt{(-2)^2+(-10)^2}=\sqrt{4+100}=\sqrt{104}=2\sqrt{26}[/tex]Answer: 2sqrt(26)