Question

Write the equation of the line passing through point (-6,0) and perpendicular to y= 3/2x

Answer 1

First, let's find the slope of our line.

Remember that the product between lines that are perpendicular is -1.

This way,

$\frac{3}{2}\cdot m=-1\rightarrow3m=-2\rightarrow m=-\frac{2}{3}$

Using the slope-point form,

$y-0=-\frac{2}{3}(x+6)\rightarrow y=-\frac{2}{3}x-4$

Therefore, the line that passes through (-6,0) and that is perpendicular to y=(3/2)x is:

$y=-\frac{2}{3}x-4$

Answer: Option B