Question

If 23.2 g of Cl2 gas occupies a volume of 255 mL at a particular temperature and pressure, what mass of the gas occupies a volume of 655 mL under the same conditions?

Answer 1

Answer

59.5974 grams

Explanation

Given data:

Mass of Cl2 gas, m = 23.2 g

Volume, V = 255 mL

What to find:

The mass of the gas that occupies a volume of 655 mL under the same conditions.

Solution:

The first step is to convert the mass of Cl2 to moles.

Moles = (Mass/Molar mass)

Molar mass of Cl2 gas = 71.0 g/mol

Moles = (23.2g/71.0 g/mol) = 0.3268 mol

This means 0.3268 mol Cl2 gas occupies a volume of of 255

Therefore, x mol Cl2 gas will occupy 655 mL volume.

To find x, cross multiply and divide both sides by 255 mL

$x=\frac{0.3268mol\times655mL}{255mL}=0.8394\text{ }mol$

The final step is to convert the moles to mass:

Moles = (Mass/Molar mass)

0.8394 mol = Mass/71.0 g/mol

Cross multiply

Mass = 0.8394 mol x 71.0 g/mol

Mass = 59.5974 grams

Therefore, 59.5974 grams of the gas occupies a volume of 655 mL under the same conditions.