Respuesta :

Solution:

Given the circle:

The length, L of the arc is;

[tex]\begin{gathered} L=\frac{\theta}{360}\times2\pi r \\ \\ \theta=90^o,r=16ft \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} L=\frac{90}{360}\times2\pi(16) \\ \\ L=8\pi ft \end{gathered}[/tex][tex]\begin{gathered} L=\frac{90}{360}\times2\pi(16) \\ \\ L=8\pi ft \end{gathered}[/tex]

CORRECT OPTION: A

Ver imagen RuebenZ493009
RELAXING NOICE
Relax