The midpoint of ST is M(-2, 1)
One endpoint is S(3, -4)
Recall that the midpoint formula is given by
[tex](x_m,y_m)=(\frac{x_1+x_2}{2},\; \frac{y_1+y_2}{2}_{})[/tex]Let us substitute the given points into the above formula
[tex]\begin{gathered} (-2_{},1_{})=(\frac{3_{}+x_2}{2},\; \frac{-4_{}+y_2}{2}_{}) \\ -2_{}=\frac{3_{}+x_2}{2},\; \; 1=\frac{-4_{}+y_2}{2}_{} \\ -2_{}\cdot2=3_{}+x_2,\; \; 1\cdot2=-4_{}+y_2 \\ -4=3_{}+x_2,\; \; 2=-4_{}+y_2 \\ -4-3=x_2,\; \; 2+4=_{}y_2 \\ -7=x_2,\; \; 6=_{}y_2 \\ x_2=-7,\; \; y_2=6 \end{gathered}[/tex]Therefore, the other endpoint is T(-7, 6)