Question

What is the volume of a cylinder with a height of 18.6 in and a base with a radius of 6.2 in, to the nearest tenth of a cubic inch?

Answer 1

Solution:

Concept:

The volume of a cylinder is given below as

$\begin{gathered} V_{\text{cylinder}}=\pi\times r^2\times h \\ \text{Where,} \\ r=6.2in \\ h=18.6in \end{gathered}$

By substituting the values in the question, we will have

$\begin{gathered} V_{\text{cylinder}}=\pi\times r^2\times h \\ V_{\text{cylinder}}=\pi\times6.2^2\times18.6 \\ V_{\text{cylinder}}=2246.188in^3 \\ V_{\text{cylinder}}\approx(nearest\text{ tenth)} \\ V_{\text{cylinder}}=2248.2in^3 \end{gathered}$

Hence,

The volume of the cylinder is = 2246.2 in³