(5 – 8x)/ square root of -8x +5 1-(-8x + 5)^(-1/2)2-(-8x + 5)^(1/2)3-(8x - 5)^(2)4) 1/(-8x + 5)

Given:-
[tex]\frac{5-8x}{\sqrt[]{-8x+5}}[/tex]To find its denominator.
So the denominator of the given function is,
[tex]\frac{1}{\sqrt[]{-8x+5}}[/tex]So the above expression can be written as,
[tex](\sqrt[]{-8x+5})^{(-\frac{1}{2})}[/tex]