Question

The position vs. time graph above represents the motion of a foam ball after being dropped. What is the instantaneous velocity at 0.8 s? (2 sig figs)

Answer 1

The position of the ball at 0.8 s is -12.5 m.

The instantaneous velocity of the ball is calculated using formula,

$v=\frac{d}{t}$

Plug in the known values,

$\begin{gathered} v=\frac{-12.5\text{ m}}{0.8\text{ s}} \\ =-15.625\text{ m/s} \end{gathered}$

Therefore, the instantaneous velocity of ball is -15.625 m/s.