1) Considering those trigonometric ratios, we can write:
[tex]\begin{gathered} \sec (x)-\tan (x) \\ \frac{1}{\cos(x)}-\frac{\sin (x)}{\cos (x)} \\ \frac{1-\sin (x)}{\cos (x)} \\ \end{gathered}[/tex]2) Since the secant is 1 over the cosine and the tangent is sine over the cosine, we can rewrite that expression as
[tex]\frac{1-\sin (x)}{\cos (x)}[/tex]3) And that's the answer
