Question

Henry has a fair number pyramid with four faces and a spinner with three equal-sized colored sections. The possible outcomes for each are shown below.What is the probability that the number pyramid will land on three and the spinner will stop on blue?What is the probability that the number pyramid will land on three and the spinner will stop on blue?

Answer 1

Answer:

The probability that the number pyramid will land on three and the spinner will stop on blue is;

$P(3\cap B)=\frac{1}{12}$

Explanation:

Given that the fair number pyramid with four faces and a spinner with three equal-sized colored sections.

The probability that the number pyramid will land on three will be;

$P(3)=\frac{n(3)}{n(Pyramid)}=\frac{1}{4}$

The probability that the spinner will stop on blue is;

$P(B)=\frac{n(B)}{n(spinner\text{)}}=\frac{1}{3}$

So, the probability that the number pyramid will land on three and the spinner will stop on blue is;

$\begin{gathered} P(3\cap B)=P(3)\times P(B)=\frac{1}{4}\times\frac{1}{3} \\ P(3\cap B)=\frac{1}{12} \end{gathered}$

Therefore, the probability that the number pyramid will land on three and the spinner will stop on blue is;

$P(3\cap B)=\frac{1}{12}$