The given equation is:
[tex]\frac{2}{3}(x-9)+4\leq24-\frac{2}{3}x[/tex]
Step 2:
[tex]\frac{2}{3}x-6+4\leq24-\frac{2}{3}x[/tex]
Step 2 is correct. In step 3 he says "I combined like terms". In this case, we have to consider the numbers that have 'x' and the ones that don't have. So, step 3 is wrong. The correct step 3 would be:
[tex]\frac{2}{3}x+\frac{2}{3}x\leq24+6-4[/tex][tex]\frac{4}{3}x\leq26[/tex]
Step 4 is correct, you can multiply both sides by 3:
[tex]4x\leq26\times3[/tex][tex]4x\leq78[/tex]
Step 5 is wrong. There is no need to do that! Also step 6 is wrong too for the same reason. And finally, step 7 is correct, you can divide both sides by 4:
[tex]x\leq19.5[/tex]
Answer: Steps 3, 4, and 5 are wrong. Step 3 is wrong because "we have to consider the numbers that have 'x' and the ones that don't have". Steps 4 and 5 are wrong because there is no need to do these steps. You can solve the inequation without them.