Question

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Answer 1

SOLUTION:

Case: Triangles similarity ratios

Given:

Required: Find the missing sides x and y

Method:

A) To find x:

$\begin{gathered} \frac{x}{9}=\frac{8}{6} \\ 6x=72 \\ Dividing\text{ both sides by 6} \\ x=12 \end{gathered}$

B) To find y

$\begin{gathered} \frac{3}{6}=\frac{y-3}{4} \\ 6(y-3)=12 \\ 6y-18=12 \\ 6y=12+18 \\ 6y=30 \\ Divide\text{ both sides by 6} \\ y=5 \end{gathered}$

Final answer:

x= 12

AND

y= 5