hello
to solve this problem, let's simplify the equation
step 1
collect like terms
[tex]\begin{gathered} \frac{3}{4}x+2-\frac{1}{3}x=12 \\ \frac{3}{4}x-\frac{1}{3}x=12-2 \\ \frac{3}{4}x-\frac{1}{3}x=10 \end{gathered}[/tex]step 2
find the LCM to resolve the fraction
the LCM of 4 and 3 is 12
[tex]\begin{gathered} \frac{3}{4}x-\frac{1}{3}x=10 \\ \frac{3(3)-1(4)}{12}x=10 \\ \frac{9-4}{12}x=10 \\ \frac{5}{12}x=10 \end{gathered}[/tex]cross multiply and solve for x
[tex]\begin{gathered} \frac{5}{12}x=10 \\ 5x=10\times12 \\ 5x=120 \\ \text{divide both sides by 5} \\ \frac{5x}{5}=\frac{120}{5} \\ x=24 \end{gathered}[/tex]x = 24