Solving the given equation for y we get:
[tex]\begin{gathered} x-3y=-6, \\ -3y=-6-x, \\ y=-\frac{6+x}{-3}=\frac{6+x}{3}, \\ y=\frac{1}{3}x+2. \end{gathered}[/tex]
Therefore, when x=0, y=2, when x=3, y=3, and when y=0, x= -6.
Answer:
Points (0,2), (3,3), and (-6,0) are solutions to the given equation.
The graph of the linear equation is as follows:
