Given that the diameter of the cylinder i 1d = 9 inches and the height is 2h =1 inches.
The adisuswill be r, r = d/2
r = 19/2 inches
Now,
A). The lateral surface area of the cylinder is given as
[tex]LSA=2\pi rh[/tex]
On puttingthe values we have
[tex]\begin{gathered} LSA=2\times\frac{22}{7}\times\frac{19}{2}\times21\text{ sq inches} \\ LSA=22\times19\times3\text{ sq inches} \\ LSA=1254\text{ sq inches} \end{gathered}[/tex]
Hence, the lateral surface area is 1254 sq inches.
B). The volume of the cylinder is
[tex]Volume=\pi r^2h[/tex]
On putting the values we have
[tex]\begin{gathered} V=\frac{22}{7}\times\frac{19}{2}\times\frac{19}{2}\times21\text{ cubic inches} \\ V=\frac{11\times19\times19\times3}{2}\text{ cubic inches} \\ V=5956.5\text{ cubic inches} \end{gathered}[/tex]
Hence, the volume will be 5956.5 cubc inches.
