We need to find the value of:
[tex]\frac{j^3\cdot k}{h^0}[/tex]
Knowing that j=-1, k=-12 and h=8. Let's see the two terms with powers seprately:
[tex]\begin{gathered} j^3=j\cdot j\cdot j=(-1)\cdot(-1)\cdot(-1) \\ \text{We know that }(-1)\cdot(-1)=1\text{ so we get:} \\ (-1)\cdot(-1)\cdot(-1)=1\cdot(-1)=-1 \\ \text{Then:} \\ j^3=-1 \end{gathered}[/tex][tex]\begin{gathered} h^0=8^0 \\ \text{And any given non-zero number raised to 0 is equal to 1 so we get:} \\ h^0=1 \end{gathered}[/tex]
If we use all these values we found in the original expression we get:
[tex]\frac{j^3\cdot k}{h^0}=\frac{(-1)^3\cdot(-12)}{8^0}=\frac{(-1)\cdot(-12)}{1}=\frac{12}{1}=12[/tex]
Which means that the answer is option C: 12.
