Question

write the equation of the line in slope intercept form, and graph using the slope and the y intercept x+4y=8

Answer 1

Solution:

The general equation of a line in slope-intercept form is given below as

$y=mx+c$

The equation of the line given is

$x+4y=8$

Concept:

We will make y the subject of the formula

$\begin{gathered} x+4y=8 \\ 4y+x-x=8-x \\ substract\text{ x from both sides} \\ 4y+x-x=8-x \\ 4y=8-x \\ divide\text{ bpoth sides by 4} \\ \frac{4y}{4}=-\frac{x}{4}+8 \\ y=-\frac{1}{4}x+2 \end{gathered}$

Hence,

The equation of the line in slope-intercept form is

$\Rightarrow y=-\frac{1}{4}x+2$