We have the following:+
[tex]\begin{gathered} 12\cdot(3\frac{2}{3}) \\ a\frac{b}{c}=\frac{a\cdot c+b}{c} \\ 3\frac{2}{3}=\frac{9+2}{3}=\frac{11}{3} \\ \frac{11}{3}=4-\frac{1}{3} \\ 12\cdot(4-\frac{1}{3}) \\ 12\cdot(4)-12(\frac{1}{3}) \end{gathered}[/tex]
