Given:
Principal, P = $342
Interest rate, r = 6.9% = 0.069
number of times compounded, n = annually = 1
Time, t = 3 years
Let's find the amount in the account after the given time.
Apply the compound interest formula:
[tex]A=P(1+r)^t[/tex]Where:
P = $342
r = 0.069
t = 3
A is the amount after the given time.
Thus, we have:
[tex]\begin{gathered} A=342(1+0.069)^3 \\ \\ A=342(1.069)^3 \\ \\ A=342(1.221611509) \\ \\ A=417.79 \end{gathered}[/tex]Therefore, the amount in the account after 3 years will be $417.79
ANSWER:
$417.79