Let the radius of the circular pond be x.
The pictorial representation of the problem is given below:
Recall the Tangent to a Circle Theorem:
It follows that we have a right triangle as shown:
Hence, the right triangle has legs with lengths 78 and x, and a hypothenuse of length 41+x.
Use the Pythagorean Theorem:
[tex]x^2+78^2=(41+x)^2[/tex]
Solve the resulting equation for the radius x:
[tex]\begin{gathered} \text{Simplify both sides of the equation:} \\ x^2+6084=x^2+82x+1681 \\ \text{Subtract }x^2\text{ from both sides:} \\ x^2+6084-x^2=x^2+82x+1681-x^2 \\ \Rightarrow6084=82x+1681 \\ \text{Swap the sides of the equation:} \\ \Rightarrow82x+1681=6084 \\ \text{Subtract 1681 from both sides:} \\ \Rightarrow82x+1681-1681=6084-1681 \\ \Rightarrow82x=4403 \\ \text{Divide both sides by 82:} \\ \Rightarrow\frac{82x}{82}=\frac{4403}{82} \\ \Rightarrow x=\frac{4403}{82}\approx54\text{ ft.} \end{gathered}[/tex]
Hence, the required radius of the pond is about 54 ft. to the nearest integer.