Question

ENTS5. Find the zeros of the quadratic function. Round to the nearest tenth if necessary.f(x) = -2x² + 3x + 1(0, 1)(0.8, 0) and (2.8, 0)(-0.3, 0) and (1.8, 0)(-1.8, 0) and (-0.3, 0)

Answer 1

Given the equation:

f(x) = -2x² + 3x + 1

We are asked to find the zeros of the quadratic function.

Using the quadratic formula:

x = -b ± √b² - 4 ac

2a

Where:

a = -2

b = 3

c = 1

Lets input into the formula:

x = -(-3) ± √(3)² - 4 (-2 * 1)

2 * -2

x = 3 ± √9 - 4 (-2)

-4

= 3 ± √9 - 4 (-2)

-4

= 3 ± √9 - 4 (-2)

-4

= 3 ± √9 - 4 (-2)

4

= 3 ± √9 + 8

4

= 3 ± √17

4

x = 1.8, -0.3

Therefore, the correct answer is (-0.3, 0) and (1.8, 0)