Consider this system of linear equations:y = 4/5x - 3y = 4/5x + 1Without graphing, determine how many solutions you would expect this system of equations to have. Explain your reasoning.

Given:
y = 4/5x - 3
y = 4/5x + 1
Looking at the above equation, they both have the same coefficient of y and also the same slope but there intercepts are different.
If we are to subtract the second equation from the first equation, we will have
0 = -4.
The above statement is incorrect because 0 ≠ 4 .
Hence, we can now say the system of equations has no solutions from the above reasoning.