Given
[tex]\begin{gathered} P_1=18.9\text{ atm} \\ V_1=100\text{ L} \\ P_2=1.7\text{ atm} \end{gathered}[/tex]The ideal gas equation is given as,
[tex]PV=nRT[/tex]Here, n is the number of moles, R is the universal gas constant and T is the temperature (constant).
Therefore,
[tex]PV=\text{const}[/tex]Hence,
[tex]P_1V_1=P_2V_2[/tex]Therefore, the final volume V_2 is given as,
[tex]V_2=\frac{P_1V_1}{P_2}[/tex]Substituting all known values,
[tex]\begin{gathered} V_2=\frac{18.9\text{ atm}\times100\text{ L}}{1.7\text{ atm}} \\ =1111.76\text{ L} \end{gathered}[/tex]Therefore, the final volume is 1111.76 L.