Given:
Two dies are thrown.
Required:
What is the probability of getting a number 1 or even number?
Explanation:
The probability
[tex]=\frac{\text{ Number of favorable cases}}{\text{ Total number of cases}}[/tex][tex]\begin{gathered} \text{ The favorable outcomes are the number 1 and the even numbers} \\ 2,4\text{ and }6,\text{ That's four outcomes. So,} \\ P(\text{ getting an even number or a 3})=\frac{4}{6}=\frac{2}{3}. \end{gathered}[/tex]Answer:
[tex]\text{ The probability is }\frac{2}{3}.[/tex]