ANSWER
The limiting reactant is NaCl
The excess reactant is Ba3(PO4)2
EXPLANATION
Given that;
The number of moles of NaCl is 2.5 moles
The number of moles of Ba3(PO4)2 is 4.5 moles
Follow the steps below to find the limiting and excess reactant
Step 1; Write the balanced equation for the reaction
[tex]\text{ 6NaCl + Ba}_3(PO_4)_2\text{ }\rightarrow\text{ 2Na}_3PO_4\text{ + 3BaCl}_2[/tex]
To determine the limiting reactant of the reaction, divide the number of moles of the reactants with their respective coefficients
In the equation above, the coefficient of NaCl is 6, and the coefficient of Ba3(PO4)2 is 1
[tex]\begin{gathered} \text{ For NaCl} \\ \text{ }\frac{\text{ 2.5}}{\text{ 6}}\text{ = 0.416 mol/wt} \\ \\ \text{ For Ba}_3PO_4\text{ } \\ \text{ }\frac{\text{ 4.5}}{1}\text{ = 4.5 mol/wt} \end{gathered}[/tex]
In the above calculations, NaCl has the least number of mol/wt, therefore, NaCl is the limiting reactant, and Ba3(PO4)2 is the excess reactant.
