Area of the circle = pi*r~2
Area = 3.14* 7.5^2
Area = 176.6
A semiclrcle is only half the area
Area of the semicircle = 176.6/2
= 88.31
I'll use proportions to find the area of the red region
red region = 100°
88.31 in^2 ------------------------ 180°
x ------------------------ 100°
x = 49 in^2
This is the result:
The area of the red section = 49 in^2
