Question

How many grams of NaOH are present in a 1.3 mole sample?

Answer 1

Answer:

52 grams

Explanations:

Given the following parameters from the question:

Moles of NaOH = 1.3 moles

The formula for calculating the mass of a compound is expressed as;'

$Mass\text{ of NaOH}=mole\times molar\text{ mass}$

Determine the molar mass of NaOH

$\begin{gathered} molar\text{ mass }of\text{ NaOH}=23+16+1 \\ molar\text{ mass of NaOH}=40g\text{/mol} \end{gathered}$

Determine the mass of NaOH

$\begin{gathered} Mass=moles\times molar\text{ mass} \\ Mass=1.3moles\times40\frac{g}{mol} \\ Mass=52grams \end{gathered}$

Hence the mass of NaOH present in a 1.3moles of the sample is 52 grams