Given:
The equation is given as,
[tex]2+\sqrt[]{3x+4}=6[/tex]The objective is to find the solution of the equation.
The solution can be calculated as,
[tex]\begin{gathered} 2+\sqrt[]{3x+4}=6 \\ \sqrt[]{3x+4}=6-2 \\ \sqrt[]{3x+4}=4 \\ 3x+4=4^2 \\ 3x+4=16 \\ 3x=16-4 \\ 3x=12 \\ x=\frac{12}{3} \\ x=4 \end{gathered}[/tex]