Answer
The volume of HClO3 in milliliters required = 44.52 mL
Explanation
Given parameters:
Molarity of HClO3, Ca = 0.100 M
Volume of KOH, Vb = 31.8 mL
Molarity of KOH, Cb = 0.140 M
What to find:
The volume, Va of HClO3 in milliliters required.
Step-by-step solution:
Step 1; Write a balanced chemical equation for the reaction.
HClO3 + KOH -----> KClO3 + H2O
Mole ratio of HClO3 to KOH is 1 : 1, that is Na = 1 and Nb = 1
Step 2: Calculate the volume of HClO3 required.
The volume of HClO3 can be calculated using
[tex]\begin{gathered} \frac{C_aV_a}{n_a}=\frac{C_bV_b}{n_b} \\ \\ \Rightarrow V_a=\frac{C_bV_bn_a}{V_an_b} \end{gathered}[/tex]
Putting the values of the given parameters into the formula above, we have
[tex]V_a=\frac{0.140M\times31.8mL\times1}{0.100M\times1}=44.52\text{ }mL[/tex]
The volume, Va of HClO3 in milliliters required = 44.52 mL
