GIVEN
Two lines AB and CD are given where AB is 2.5 units long and CD is 3.25 units long.
SOLUTION
The point G is collinear to the line CD and is between C and D. This can be seen in the image below:
The length of line DG is twice the length of line CG. This means that if CG is x units long, then:
[tex]DG=2x[/tex]
Add the lengths of DG and CG and we will get the length of CD. Therefore:
[tex]\begin{gathered} DG+CG=CD \\ \therefore \\ 2x+x=3.25 \\ 3x=3.25 \\ x=\frac{3.25}{3} \\ x=1\frac{1}{12} \end{gathered}[/tex]
Therefore, the length of CG will be:
[tex]\overline{CG}=1\frac{1}{12}\text{ units}[/tex]
