Evaluate the expression when x = 2/3 and y = 2/5.x-3yWrite your answer in simplest form.

Given:
[tex]x-3y\text{ ; x=}-\frac{2}{3}\text{ ; y=}\frac{2}{5}[/tex][tex]\begin{gathered} x-3y=-\frac{2}{3}-3(\frac{2}{5}) \\ =-\frac{2}{3}-\frac{6}{5} \\ =\frac{-10-18}{15} \\ =-\frac{28}{15} \end{gathered}[/tex]