Answer:
Explanation:
Let Musa's mark = m
Adenike obtained 19 marks more than Musa, therefore:
Adenike's mark, a = m+19
If Adenike had obtained one and a half times her own mark, she would have scored 6 marks more than twice Musa's mark.
[tex]\begin{gathered} \text{ One and half times Adenike's mark}=1\frac{1}{2}a \\ 6\text{ more than twice Musa's mark}=2m+6 \\ \implies1\frac{1}{2}a=2m+6 \end{gathered}[/tex]Substitute a=m+19 and solve for m: