Question

How do you evaluate for x = 3 and y = 6?

Answer 1

Solution

Given

$\begin{gathered} \frac{x^3y^5}{x^5y^2} \\ \\ x=3\text{ and }y=6 \\ \frac{3^3\times6^5}{3^5\times6^2}=\frac{3^3\times2^5\times3^5}{3^5\times2^2\times3^2} \end{gathered}$

$\begin{gathered} =\frac{2^5\times3^{3+5}}{2^2\times3^{5+2}} \\ \\ =\frac{2^5\times3^8}{2^2\times3^7} \\ \\ =2^{5-2}\times3^{8-7} \\ \\ =2^3\times3=24 \end{gathered}$

Correct option D