This problem could be solve with the Simple of Three Rule:
[tex]\begin{gathered} 20\text{ f}eet\to240\text{ bricks} \\ 1\text{foot }\to x\text{ bricks} \\ x=1foot\cdot\frac{240\text{ bricks}}{20\text{ f}eet}=\frac{240}{20}bricks=12\text{ bricks} \end{gathered}[/tex]You need 12 bricks for a 1 foot high wall